Answer: [tex]\bold{\bigg(\dfrac{1}{2},2\dfrac{1}{2}\bigg)}\qquad \implies \qquad \bold{\bigg(\dfrac{1}{2},\dfrac{5}{2}\bigg)}[/tex]
Step-by-step explanation:
y = x + 2 x + y = 3
Solve using Substitution Method by replacing y with x + 2:
x + (x + 2) = 3
2x + 2 = 3
2x = 1
x = [tex]\dfrac{1}{2}[/tex]
Next, replace x with 1/2 in one of the original equations and solve for y:
y = x + 2
= [tex]\dfrac{1}{2}[/tex] + 2
= [tex]2\dfrac{1}{2}[/tex]
Answer:
x = 1/2
y = 5/2
Step-by-step explanation:
So we're gonna use the elimination method, by eliminating one of x or y to find the value of the other one.
y = x + 2 --------------(1)
x + y = 3 --------------(2)
In (1), x is in LHS and y is in RHS. To make things simpler, we take both x and y to the same side.
y = x + 2
y - x = x + 2 - x ( take x to the other side)
y - x = 2-------------------------(3)
Note that in (2), x is positive and in (3), x is negative. So by adding these two, we can single out y because +x and -x cancels out. So we can eliminate x.
(3) + (1) : (x+y) + (y- x) = 3 + 2
2y = 5
y = 5/2
Substituting y = 5/2 for (1),
5/2 - x = 2
5/2 = 2 + x
5/2 - 4/2 = x
x = 1/2
∴ x = 1/2
y = 5/2
Hope i helped you :)
