ANSWER
[tex]f(x) = (x -7)(x - 5) {(x - 5)}(x + 2)[/tex]
EXPLANATION
If the polynomial has a root -2, with multiplicity 1, then (x+2) is a factor.
If the polynomial has root, 7 with multiplicity 1, then (x-7) is a factor.
If the polynomial has root 5, with multiplicity 2, then (x-5)² is a factor of the polynomial.
The fully factored form of the polynomial is
[tex]f(x) =a (x + 2)(x - 7) {(x - 5)}^{2} [/tex]
It was given that the polynomial has a leading coefficient of 1.
Hence a=1.
This implies that,
[tex]f(x) =(x + 2)(x - 7) {(x - 5)}^{2}[/tex]
Or
[tex]f(x) = (x -7)(x - 5) {(x - 5)}(x + 2)[/tex]
Answer:
f(x) = (x -7)(x - 5) {(x - 5)}(x + 2) the answer is D
Step-by-step explanation:
