Answer:
[tex]304\dfrac{4}{7}\ milliliters[/tex]
Step-by-step explanation:
If there are 3 milliliters of compound A used for every 4 milliliters of compound B, then we can denote that we use 3x milliliters of compound A and 4x milliliters of compound B to get 533 milliliters of the drug. Thus,
[tex]3x+4x=533,\\ \\7x=533,\\ \\x=\dfrac{533}{7}\ milliliters.[/tex]
Hence, a chemist must take
[tex]4\cdot \dfrac{533}{7}=\dfrac{2132}{7}=304\dfrac{4}{7}\ milliliters[/tex]
of compound B.
Answer:
228.43 ml
Step-by-step explanation:
The ratio of compound A to compound B will be; 4: 3
4:3 is the same as 4x:3x where 4x is compound A and 3x is compound B.
We can solve for "x":
If amount of compound A is 4x and compound B is 3x;
Then; 4x + 3x = 533
7 x = 533
x = 533/7
Then amount of compound B is 3x = 3(533/7)
= 228.43 ml
