Respuesta :
Write both sides as powers of [tex]e[/tex]:
[tex]\ln(x+4)=-1\implies e^{\ln(x+4)}=e^{-1}\implies x+4=e^{-1}[/tex]
since [tex]b^{\log_ba}=a[/tex]. Then
[tex]x=e^{-1}-4\approx-3.63[/tex]
Write both sides as powers of [tex]e[/tex]:
[tex]\ln(x+4)=-1\implies e^{\ln(x+4)}=e^{-1}\implies x+4=e^{-1}[/tex]
since [tex]b^{\log_ba}=a[/tex]. Then
[tex]x=e^{-1}-4\approx-3.63[/tex]