Answer:
= 5.26 × 10^-7 M
Explanation:
We know that;
[H3O+][OH-] = 1 x 10^-14
Therefore;
Given; OH− concentration = 1.9x10^−8 M
Then; [H3O+] = (1 x 10^-14)/[OH-]
= (1 x 10^-14)/(1.9x10^−8)
= 5.26 × 10^-7 M
Taking into account the definition of pH and pOH, the concentration of H₃O⁺ is 5.25×10⁻⁷ M.
First of all, pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.
The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or H₃O⁺:
pH= - log [H⁺]= - log [H₃O⁺]
Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:
pOH= - log [OH⁻]
The following relationship can be established between pH and pOH:
pOH + pH= 14
In this case, [OH⁻]= 1.9×10⁻⁸ M. Then, the pOH can be calculated as:
pOH= - log (1.9×10⁻⁸ M)
Solving:
Now, you can calculated the pH, considering the relationship between pH and pOH:
pOH + pH= 14
7.72 + pH=14
pH=14 - 7.72
Finally, the concentration of H₃O⁺ can be calculated from the definition of pH:
pH= - log [H₃O⁺]
6.28= - log [H₃O⁺]
[H₃O⁺]= 10⁻⁶ ²⁸
In summary, the concentration of H₃O⁺ is 5.25×10⁻⁷ M.
Learn more about pH and pOH:
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