Answer:
[tex]\large\boxed{\text{The slope}\ m=3}[/tex]
Step-by-step explanation:
The slope-intercept form of an equation of a line:
[tex]y=mx+b[/tex]
m - slope
b - y-intercept
We have the equation of a line in the standard form:
[tex]12x-4y=3[/tex]
Convert to the slope-intercept form:
[tex]12x-4y=3[/tex] subtract 12x from both sides
[tex]-4y=-12x+3[/tex] divide both sides by (-4)
[tex]y=\dfrac{-12}{-4}x+\dfrac{3}{-4}\\\\y=3x-\dfrac{3}{4}[/tex]
Answer: The required slope of the given line is 3.
Step-by-step explanation: Given that Helaine graphed the following equation :
[tex]12x-4y=3~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)[/tex]
We are to find the slope of the line.
We know that
the slope-intercept form of a straight line is given by
[tex]y=mx+c,[/tex] where m is the slope of the line.
From equation (i), we have
[tex]12x-4y=3\\\\\Rightarrow 4y=12x-3\\\\\Rightarrow y=\dfrac{12x-3}{4}\\\\\\\Rightarrow y=3x-\dfrac{3}{4}.[/tex]
Comparing with the slope-intercept form, we get
slope, m = 3.
Thus, the required slope of the given line is 3.
