Answer:
0.23 T
Explanation:
The magnetic force exerted on the antiproton must be equal to the centripetal force, since it is a circular motion, therefore we can write:
[tex]qvB = m\frac{v^2}{r}[/tex]
where
[tex]q=1.6\cdot 10^{-19}C[/tex] is the charge of the antiprotons
[tex]v=5.70\cdot 10^7 m/s[/tex] is the speed of the antiprotons
B is the magnitude of the magnetic field
[tex]m=1.67\cdot 10^{-27}kg[/tex] is the antiproton mass
r = 2.60 m is the radius of the orbit
Solving the equation for B, we find the strength of the magnetic field:
[tex]B=\frac{mv}{qr}=\frac{(1.67\cdot 10^{-27} kg)(5.70\cdot 10^7 m/s)}{(1.6\cdot 10^{-19}C)(2.60 m)}=0.23 T[/tex]
