Answer:
T = 0.444 sec
f = 2.25 Hz
Explanation:
Mass of the object = m = 50g = 0.05 kg
Spring constant = k = 10N/m
The time period of mass attached to a spring is calculated as:
[tex]T=2\pi\sqrt{\frac{m}{k} }[/tex]
Using the values in the formula, we get:
[tex]T=2\pi\sqrt{\frac{0.05}{10} }=0.444[/tex]
Thus the time period is 0.444 sec.
Frequency is the reciprocal of the time period.
[tex]f=\frac{1}{T}\\\\ f=\frac{1}{0.444} =2.25[/tex]
Thus the frequency of oscillation is 2.25 Hertz
