Based on the graph, the soccer ball is not moving from C) from 4.5 to 5.0 seconds
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Further explanation
Acceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem!
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This problem is about Average Speed
We will use this following formula:
[tex]\texttt{Average Speed} = \texttt{Distance} \div \texttt{Time Taken}[/tex]
From 4.5 to 5.0 seconds , there is no change in distance of the ball.
t₁ = 4.5 → s₁ = 65 m
t₂ = 5.0 → s₂ = 65 m
[tex]\texttt{Average Speed} = (65 - 65) \div (5.0 - 4.5)[/tex]
[tex]\texttt{Average Speed} = 0 \div 0.5[/tex]
[tex]\texttt{Average Speed} = 0 \texttt{ m/s}[/tex]
Since the average speed is zero, the ball doesn't move from 4.5 to 5.0 seconds.
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Learn more
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
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Answer details
Grade: High School
Subject: Physics
Chapter: Kinematics
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Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Projectile , Motion , Horizontal , Vertical , Release , Point , Ball , Wall
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