Answer:
B
Step-by-step explanation:
x - 3 = [tex]\sqrt{4x-7}[/tex]
square both sides to get rid of square root
x^2 -6x + 9 = 4x - 7 , but remember 4x - 7 can't be less than 0 since it was square roots can't be less than 0
simplify the equation
x^2 - 10x + 16= 0
x = 8, x= 2
but x cannot equal 2, because if we plug in 2, the square root will be negative,
so x can only equal 8
so B is correct.
I'm not the best at quadratics, so pls comment if something is wrong
