Respuesta :
4x^2+4x-5x-5=0
4x(x+1)-5(x+1)=0
(x+1)=0. 4x-5=0
x=-1
x=5/4
4x(x+1)-5(x+1)=0
(x+1)=0. 4x-5=0
x=-1
x=5/4
Answer:
D. 5/4
F. -1
Step-by-step explanation:
The quadratic formula x = [tex]\frac{-b +/- \sqrt{b^2 - 4ac} }{2a}[/tex]
The given equation is 4x^2 - x -5 = 0
Here a = 4, b = -1, and c = -5.
Plug in these values into the formula.
x = [tex]\frac{-(-1) +/- \sqrt{(-1)^2 - 4*4*-5} }{2*4}[/tex]
x= [tex]\frac{1 +/- \sqrt{1 + 80} }{8}[/tex]
x = (1+/- 9)/8
x = (1+9)/8 and x = (1 -9)/8
x = 10/8 and x = -8/8
x = 5/4 and x = -1
The answers are
D. 5/4
F. -1
Hope this will helpful.
Thank you!