The right answer is 15%.
The D allele is dominant, ie in the case of heterozygosity, it is expressed.
When we cross between the male and the female. we will have 50% "Dd" and 50% "dd".
50% (frequency of 0.5) of the descendant will carry the dominant gene but only 30% (frequency of 0.3) among them will express the disease, therefore it is necessary to make the multiplication:
0.5 * 0.3 = 0.15 (equivalent to 15% of the descendence).