Answer:
It would cross at (0, -1)
y = mx + c
The 'c' is the y intercept
Step-by-step explanation:
A line crossing y-axis has x coordinate zero at that point of crossing. The considered line [tex]y=x-1[/tex] crosses y-axis at point [tex](0, -1)[/tex]
Suppose that the line considered be of the form [tex]y = f(x)[/tex]
The equation for y-axis is x = 0
Thus, intersection between both the curves is obtained by putting x = 0 in the considered function.
We get [tex]x=0[/tex] , and [tex]y=f(0)[/tex], Thus, the coordinate point of intersection with y-axis is [tex](0, f(0))[/tex]
And the equation for x-axis is [tex]y = 0[/tex]
Thus, its intersection with given function is at y= 0 and y such that [tex]f(x) = 0[/tex]
For the given case, we have the considered line as [tex]y = x- 1[/tex]
To get its intersection with y-axis(which is x = 0), we put x = 0 in the given equation of line.
Thus, [tex]y = x - 1 = 0-1 = -1[/tex]
Thus, the point on the y-axis where the line [tex]y = x-1[/tex] intersects it is [tex](0, -1)[/tex]
Learn more about functions crossing axes here:
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