Answer:
0.13 J/g.°C.
Explanation:
- To solve this problem, we can use the relation:
Q = m.c.ΔT,
where, Q is the amount of heat absorbed by lead (Q = 29.0 J).
m is the mass of lead (m = 15.0 g).
c is the specific heat capacity of lead (c = ??? J/g.°C).
ΔT is the temperature difference (final T - initial T) (ΔT = 37 °C - 22 °C = 15.0 °C).
∵ Q = m.c.ΔT
∴ c = Q/m.ΔT = (29.0 J)/(15.0 g)(15.0 °C) = 01288 J/g.°C ≅ 0.13 J/g.°C.
