1. Answer;
= 5.4×10-6 g AgBr
Explanation;
AgBr(s) → Ag+(aq) + Br-(aq) Ksp = 3.3×10^-13
[Ag+][Br-] = Ksp = 3.3×10^-13 = X²
X = 5.7×10^-7 M = [Ag+] = mol/L AgBr that dissolve
1 mole of AgBr = 187.8 g
Therefore;
= 0.05 L × (5.7 × 10^-7 mol/L) × (187.8 g /mol)
= 5.4×10-6 g AgBr
2. Answer and explanation;
The two factors that accounts for increased rate of chemical reaction when temperature is increased are:
- Energy factor; enough energy in the collision for the formation of an activated complex, where bonds are breaking and new ones forming. When temperature is increased, a greater number of molecular collisions possess enough energy to activate the reaction.
- Frequency of collisions increases; an increase in temperature makes particles move faster and collide more frequently, increasing the possibility of a reaction be-tween them.
More important factor; Energy factor is more important.