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) determine the henry's law constant for ammonia in water at 25°c if an ammonia pressure of 0.022 atm produces a solution with a concentration of 1.3 m.

a.59 m/atm

b.0.029 m/atm

c.0.038 m/atm

d.35 m/atm

e.0.017 m/atm

Respuesta :

superman1987

Answer:

a. 59 m/atm

Explanation:

  • To solve this problem, we must mention Henry's law.
  • Henry's law states that at a constant temperature, the amount of a given gas dissolved in a given type and volume of liquid is directly proportional to the partial pressure of that gas in equilibrium with that liquid.
  • It can be expressed as: C = KP,

C is the concentration of the solution (C = 1.3 M).

P is the partial pressure of the gas above the solution (P = 0.022 atm).

K is the Henry's law constant (K = ??? M/atm),

∵ C = KP.

∴ K = C/P = (1.3 M)/(0.022 atm) = 59.0 M/atm.

mahima6824soni

Henry's law constant for ammonia is 59 m/atm

The correct option is A.

What is Henry's law?

Henry's law says that the amount of gas dissolved in a liquid is directly proportional to the partial pressure above the liquid.

[tex]C = kp[/tex]

Given,

Concentration is 1.3 m

Pressure is 0.022 atm

[tex]1.3m= k\times0.002\\\\k = \dfrac{1.3m}{0.002} = 59.0\;m/atm.[/tex]

Thus, the correct option is(A)  59 m/atm

Learn more about Henry law, here:

https://brainly.com/question/24911770

 

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