Answer:
Proved by ASA congruence rule.
Step-by-step explanation:
Given the parallelogram TALK. We have to prove that TA is congruent to LK and AL is congruent to KT.
∵ TALK is a parallelogram,
AL is parallel to segment TK and TA is parallel to KL and Line TL is a transversal.
⇒ ∠1 ≅ ∠ 4 and ∠2 ≅ ∠ 3
In ΔTLK and ΔTLA
∠1 = ∠ 4 (∵Alternate angles)
∠2 = ∠ 3 (∵Alternate angles)
TL=TL (∵Common)
By ASA rule, ΔTLK ≅ ΔTLA
∴ By CPCT(Corresponding Parts of Congruent Triangles), TA ≅ LK and segment AL ≅ KT
Hence Proved
Answer:
asa and ctptc or whatever thats called
Step-by-step explanation:
