Sasha invests $1000 that earns 8% interest compounded annually. Write a function that describes the value, V, of the investment after t years.

Respuesta :

Answer:

The function is defined as [tex]V = a (1 +r)^{t}[/tex] and Sasha investment of  $1000 that earns 8% interest compounded annually becomes $1080 .

Step-step- Explanation:

As the function is  defined by

[tex]V = a (1 +r)^{t}[/tex]

Where a is the initial value , t is time in years and r is the rate of interest in the decimal form .

As given

Sasha invests $1000 that earns 8% interest compounded annually.

a = $1000

8% is written in the decimal form .

[tex]= \frac{8}{100}[/tex]

= 0.08

t = 1 years

Putting all the values in the formula

[tex]V = 1000(1 +0.08)^{1}[/tex]

[tex]V = 1000(1.08)[/tex]

V = $1080

Therefore the function is defined as [tex]V = a (1 +r)^{t}[/tex] and Sasha investment of  $1000 that earns 8% interest compounded annually becomes $1080 .

Answer:

[tex]V(t)+1000(1.08)^{t}[/tex]

Step-by-step explanation:

This function describes the value V of the investment after t years.