[tex]\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &1350\\ r=rate\to 30\%\to \frac{30}{100}\dotfill &0.30\\ t=\textit{elapsed time}\dotfill &5\\ \end{cases} \\\\\\ A=1350(1-0.30)^5\implies A=1350(0.7)^5\implies A=226.8945[/tex]
