For the cement bag we can say as per its force diagram we will have
[tex]2F - mg = ma[/tex]
here we will have
[tex]m = 50 kg[/tex]
[tex]a = 2 m/s^2[/tex]
now we will have
[tex]F = \frac{mg + ma}{2}[/tex]
now plug in all data
[tex]F = \frac{50(9.8 + 2)}{2}[/tex]
[tex]F = 295 N[/tex]
so the pulling force will be 295 N