Respuesta :

Answer:

See attachment.

Step-by-step explanation:

Given equation [tex]y=\ln x+1[/tex]

We have to plot the graph for the given equation [tex]y=\ln x+1[/tex]

finding x and y intercept,

[tex]\mathrm{x-intercept\:is\:a\:point\:on\:the\:graph\:where\:}y=0[/tex]

[tex]y\mathrm{-intercept\:is\:the\:point\:on\:the\:graph\:where\:}x=0[/tex]

Substitute y= 0 in given equation, We get,

[tex]\ln x+1=0 \Rightarrow x=\frac{1}{e}[/tex]

The graph does not have any y intercept.

For Horizontal and vertical asymptotes ,

[tex]\mathrm{Logarithmic\:function\:of\:the\:form}\:f\left(x\right)\:=\:c\cdot \:log_a\left(x+h\right)+k[/tex]

[tex]\mathrm{has\:a\:vertical\:asymptote}\:x=-h[/tex]

Thus, the vertical asymptote is x=0

[tex]\mathrm{Logarithmic\:function\:of\:the\:form}\:f\left(x\right)\:=\:c\cdot \:log_a\left(x+h\right)+k[/tex]

thus, the graph do not have any horizontal asymptote.

Thus, attachment is the graph of the given equation  [tex]y=\ln x+1[/tex].

Ver imagen athleticregina
shristiparmar1221

This question is based on graph. Simply, plot the graph of given equation by using intercept of x and y.

Given:

Equation of  graph  y = ln x + 1.

We have to plot the graph for the given equation.  

Now we have to determined  x and y intercept on graph.

So, firstly we find x-intercept, put y=0 in given equation.

We get,

[tex]ln x +1=0\Rightarrow x=\dfrac{1}{e} \Rightarrow x= 0.36[/tex]

Now, we find y-intercept, put x=0 in given equation.

We get,

y=ln(0) +1

ln(0) is not exist. So, the graph does not have any y-intercept.

Now, plot this points on graph.

Thus, below attachment is the graph of the given equation.

For more details, please prefer this link:

https://brainly.com/question/11616742  

Ver imagen shristiparmar1221

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