Answer:
The area of the parallelogram is 55 square unit.
Step-by-step explanation:
The area of a parallelogram is
[tex]A=\frac{1}{2}\times base\times height[/tex]
It is given that the vertices of the parallelogram are P(-2, -5), Q(9, -5), R(1, 5), S(12, 5).
Plot these points on a coordinate plane, and draw a perpendicular on PQ from the point R.
From the graph is clear that length of PQ is 11 and the height of the parallelogram is 10. So, the area of a parallelogram is
[tex]A=\frac{1}{2}\times 11\times 10[/tex]
[tex]A=55[/tex]
Therefore the area of the parallelogram is 55 square unit.
