Ans: around 547 g of Mg will react completely with HCl
Given reaction:
Mg(s) + 2HCl (aq) → MgCl2(aq) + H2(g)
Volume of HCl, V= 8.3 L
Molarity of HCl, M = 5.5 M i.e. 5.5 moles/L
# Moles of HCl = M*V = 5.5 moles/L 8.3 L = 45.65 moles
Based on the reaction stoichiometry 1 mole of Mg reacts with 2 moles of HCl
Therefore moles of Mg that would react completely with 45.7 moles of HCl is:
= 45.65/2 = 22.825 moles
Atomic mass of Mg = 24 g/mole
Mass of Mg = 22.825 moles*24 g/mole = 547.8 g
