Respuesta :
Answer: [tex]N_2+3H_2\rightarrow 2NH_3[/tex]
[tex]\frac{N_2}{H_2}=\frac{1}{3}[/tex]
[tex]\frac{N_2}{NH_3}=\frac{1}{2}[/tex]
[tex]\frac{H_2}{NH_3}=\frac{3}{2}[/tex]
Explanation:
According to the law of conservation of mass, mass can neither be created nor be destroyed, and remains conserved. The mass of products must be same as that of the reactants.
Thus the number of atoms of each element must be same on both sides of the equation so as to keep the mass same and thus balanced chemical equations are written.
[tex]N_2+3H_2\rightarrow 2NH_3[/tex]
Thus the stochiometric coefficients of [tex]N_2[/tex] [tex]H_2[/tex] and [tex]NH_3[/tex] are 1, 3 and 2 respectively.
