Answer:
h(t) = 144·t - 16·t^2 = 16·t·(9 - t) = 0
9 - t = 0 --> t = 9
The ball will hit the ground after 9 seconds.
The ball will hit the ground before rebounding after 9 seconds .
Given that a ball tossed in the air from the ground level reaches a height of h feet . The equation given for it is -
[tex]h = 144t - 16t^{2}[/tex] which is time dependent
We have to find the time t when the ball will hit the ground before rebounding.
Thus for this to happen , at the instant when the ball first touches the ground, the height of the ball is zero from the ground , just before rebounding.
Putting h = 0 in the above equation ,
[tex]144t - 16t^{2} = 0[/tex]
⇒ [tex]16t^{2} = 144t[/tex]
⇒ [tex]16t = 144[/tex]
∴ [tex]t = 9[/tex]
Thus the ball will hit the ground after 9 seconds .
To learn more about parameterized equations, refer -
https://brainly.com/question/19790478
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