A football is throw by a quarterback to a receiver

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Professor1994 Professor1994 · Answer 1 · 2019-02-03T06:11:16+01:00

Answer:

(2.5,10.5)

Step-by-step explanation:

In the abscissa (x), A is in the middle point between 0 and 5:

[tex]x=\frac{0+5}{2}\\ x=\frac{5}{2}\\ x=2.5[/tex]

In the ordinate (y), A is in the middle point between 9 and 12:

[tex]y=\frac{9+12}{2}\\ y=\frac{21}{2}\\ y=10.5[/tex]

Then, the coordinates of point A are:

A=(x,y)→A=(2.5,10.5)

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AlonsoDehner AlonsoDehner · Answer 2 · 2019-02-03T07:06:23+01:00

Answer:

(2.5,10.5)

Step-by-step explanation:

Given that a ball is thrown verically upwards with an initial velocity. We know that the path is a trajectory as a parabola.

From graph we find that horizontal is in yards and vertical is in feet.

WE have to find the coordinates of A

When ball is thrown upward, acceleration due to gravity is -32 ft/s^2

Since height = s=[tex]ut-16t^2[/tex]+h0

we get h0 as initial height.

But without any calculation from the graph we find out these coordinates as

x coordinate = 2.5(since in the middle of 0 and 5)

y coordinate = 10.5(since in the middle of 9 and 12)