Answer:
In the given composite figure:
Labelled the figure:
In a square ABCD figure:
Each side is of 18 m each
Area of a square is given by:
[tex]\text{Area of square} = (\text{Side})^2[/tex]
Then;
[tex]\text{Area of square ABCD} = (18)^2 = 324 m^2[/tex]
Now, In right angle triangle CEF:
Area of a right angle triangle is given by:
[tex]\text{Area of triangle} = \frac{1}{2}(\text{Base}) \cdot (\text{Height})[/tex]
In a a triangle CEF:
Base = CE = 8 m and Height = CF = 16 m
then;
[tex]\text{Area of triangle CEF} = \frac{1}{2}(8) \cdot (16)=4 \cdot 16 = 64 m^2[/tex]
Similarly in triangle DCF:-
Base = CD = 18 m
Height = CF = 16 m
then;
[tex]\text{Area of triangle DCF} = \frac{1}{2}(18) \cdot (16)=9 \cdot 16 = 144 m^2[/tex]
Thus:
area of composite figure =Area of square ABCD + Area of triangle CEF + Area of triangle DCF
Area of this composite figure= 324 +64+144 = 532 square meter.
Therefore, area of this figure is 532 meter square.
