Factor the trinomial below.
12x^2 - 32x - 12

A. 4(3x+3)(x-1)

B. 4(3x+1)(x-3)

C. 4(3x+6)(x-2)

D. 4(3x+2)(x-6)

Respuesta :

4(3x^2 - 8x - 3)
4(3x + 1)(x - 3)
the answer to the question is b

The factorization of the trinomial 12x² - 32x - 12, by the use of mid-term factorization method is 4(3x + 1)(x - 3). Hence, option B is the right choice.

How to factor a quadratic expression?

A quadratic expression of the form ax² + bx + c is factored by using the mid-term factorization method, which suggests that b should be broken in such two components that their product = ac. After this, we can factorize using the grouping method.

How to solve the question?

In the question, we are asked to factor the trinomial 12x² - 32x - 12.

As we can see it's a quadratic expression, we will use the mid-term factorization method to factorize it.

On comparing 12x² - 32x - 12 to ax² + bx + c, we can say that a = 12, b = -32, and c = -12.

Now, as per the mid-term factorization method, we will try to break b = -32, in such two numbers that their product = ac = 12*(-12) = -144.

We get this break as -36 and 4. Substituting these in our expression, we get:

12x² - 32x - 12

= 12x² - 36x + 4x -12 {Breaking mid-term}

= 12x(x - 3) + 4(x - 3) {Grouping}

= (12x + 4)(x - 3) {Grouping}

= 4(3x + 1)(x - 3) {Taking common}.

Therefore, the factorization of the trinomial 12x² - 32x - 12, by the use of mid-term factorization method is 4(3x + 1)(x - 3). Hence, option B is the right choice.

Learn more about mid-term factorization at

brainly.com/question/25829061

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