Answer: ∆CAN ≅Δ BRO by SSS congruence rule.
Step-by-step explanation:
It is given that CARBON is a regular polygon.
Since all sides of a regular polygon are equal.
Therefore, CA=AR=RB=BO=ON=NC .....................(1)
In ΔANO and ΔORA
∠ANO=∠ORA [each 90°]
OA=OA [same]
NO=AR [from (1)]
∴ ΔANO ≅ ΔORA by RHS congruence rule
⇒NA=OR [by CPCT]
Now in ∆CAN and Δ BRO..............(2)
CN=OB=CA=RB.............[from (1)]
NA= OR [from (2)]
∴∆CAN ≅Δ BRO by SSS congruence rule.
