Answer:
11.0 kg m/s
Explanation:
The impulse exerted on the cart is equal to its change in momentum:
[tex]I=\Delta p=m\Delta v[/tex]
where
m = 5.0 kg is the mass of the cart
[tex]\Delta v=2.2 m/s[/tex] is its change in speed
Substituting numbers into the equation, we find
[tex]I=(5.0kg)(2.2 m/s)=11 kg m/s[/tex]
Solution:
In this question we have given
mass of Cart=5Kg
change in speed,[tex]\Delta v=2.2\frac{m}{s}[/tex]
We have to find, Impulse, I=?
Impulse :
Impulse of a body is equla to its change in momentum.
Therefore,
Impulse of cart is equal to its change in momentum:
[tex]I=\Delta p\\I=m\Delta v[/tex]................(1)
Put values of [tex]\Delta v[/tex], and m in eq(1)
[tex]I=(5.0kg)(2.2\frac{m}{s} )\\I=11 kg\frac{m}{s}[/tex]
Therefore, the impulse of the cart,[tex]I=11 kg\frac{m}{s}[/tex]
