Answer:
89–100
Step-by-step explanation:
Let x represent the grade on the fifth test. The average for 5 tests wants to be between 80 and 90, so we have ...
80 ≤ (78 +62 +91 +80 +x)/5 ≤ 90
Multiplying by 5 gives
400 ≤ 311 +x ≤ 450
Subtracting 311 gives the range for the fifth test grade.
89 ≤ x ≤ 139
Since the maximum available score is 100, the range on the 5th test for an overall B grade is ...
89 ≤ x ≤ 100 . . . . where x is the grade on the 5th test