Respuesta :
Answer:
$3,799.20
Step-by-step explanation:
We presume your formula is intended to be ...
M = Pm(1 + m)^(na)/((1 + m)^(na) - 1)
where M is the monthly payment, m is the monthly interest rate, n is 12, and a is the number of years.
This formula gives ...
M = 3500·(.08/12)·(1 + (.08/12))^(12·2)/((1 + (.08/12))^(12·2) -1) ≈ 158.30
The total payback will be the sum of 24 of these payments:
payback = 24×$158.30 = $3,799.20
The total payback after 2 years is $3799.20.
Given
An amount of $3,500 loan at 8% annual interest with monthly payments for two years.
Monthly payback;
The formula is used to total payback is;
[tex]\rm M =\dfrac{Pm(1+m)^{na}}{(1+m)^{na}-1}[/tex]
Where M is the monthly payment, m is the monthly interest rate, n is 12, and a is the number of years.
Substitute all the values in the formula;
[tex]\rm M =\dfrac{Pm(1+m)^{na}}{(1+m)^{na}-1}\\\\ M =\dfrac{3500\times \dfrac{0.08}{12}(1+ \dfrac{0.08}{12})^{12\times 2}}{(1+ \dfrac{0.08}{12})^{12\times 2}-1}\\\\ M = \rm \dfrac{23.33\times 1.17}{1.17-1}\\\\M=\dfrac{27.29}{0.17}\\\\M=158.30[/tex]
Therefore,
The total payback will be;
[tex]= 158.30 \times 24\\\\=3,799.20[/tex]
Hence, the total payback after 2 years is $3799.20.
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