Answer:
11 units
Step-by-step explanation:
Given : She has mapped the arrangement on a coordinate pane. A,B and C represent the sofas, V1 and V2 are decorative vases and AQ the aquarium
To Find: The distance between V1 and the aquarium.
Solution:
Referring the given image
We can have the coordinates of V1 and AQ
Coordinates of V1 :[tex](x_{1}, y_{1}) =(-6,5)[/tex]
Coordinates of AQ :[tex](x_{2}, y_{2}) =(5,5)[/tex]
Now To find distance use distance formula
[tex]d=\sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}[/tex]
[tex]d=\sqrt{(5-[-6])^{2} + (5-5)^{2}}[/tex]
[tex]d=\sqrt{11)^{2} + (0)^{2}}[/tex]
[tex]d=\sqrt{11)^{2}}[/tex]
[tex]d=\sqrt{121}[/tex]
[tex]d=11[/tex]
Hence The distance between V1 and the aquarium is 11 units
