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The function below is written in vertex form or intercept form. Rewrite them in standard form and show your work.

y = (x+4)(x+3)

Respuesta :

Answer:

The standard form as [tex]y=x^2+7x+12[/tex]

Step-by-step explanation:

Given: A function which is written in vertex form or intercept form.

We have to re-write it  in standard form that in terms of [tex]y=ax^2+bx+c[/tex]

Given[tex]y = (x+4)(x+3)[/tex]

Multiply each term ,

[tex]y = x(x+3)+4(x+3)[/tex]

[tex]y= x^2+3x+4x+12[/tex]

[tex]y=x^2+7x+12[/tex]

Thus , we have obtained the standard form as [tex]y=x^2+7x+12[/tex]

Answer:

y = x²+7x+12

Step-by-step explanation:

Given equation is :

y = (x+4)(x+3)

We have to transform above equation into standard form.

y = ax²+bx+c is standard form of quadratic equation.

y = (x+4)(x+3)

Multiply each term of first parentheses  to each term of second parentheses.

y = x(x+3)+4(x+3)

y = x(x)+x(3)+4(x)+4(3)

y = x²+3x+4x+12

add the coeficients of like terms

y = x²+7x+12 is standard form of given equation.