Respuesta :
Answer:
The standard form as [tex]y=x^2+7x+12[/tex]
Step-by-step explanation:
Given: A function which is written in vertex form or intercept form.
We have to re-write it in standard form that in terms of [tex]y=ax^2+bx+c[/tex]
Given[tex]y = (x+4)(x+3)[/tex]
Multiply each term ,
[tex]y = x(x+3)+4(x+3)[/tex]
[tex]y= x^2+3x+4x+12[/tex]
[tex]y=x^2+7x+12[/tex]
Thus , we have obtained the standard form as [tex]y=x^2+7x+12[/tex]
Answer:
y = x²+7x+12
Step-by-step explanation:
Given equation is :
y = (x+4)(x+3)
We have to transform above equation into standard form.
y = ax²+bx+c is standard form of quadratic equation.
y = (x+4)(x+3)
Multiply each term of first parentheses to each term of second parentheses.
y = x(x+3)+4(x+3)
y = x(x)+x(3)+4(x)+4(3)
y = x²+3x+4x+12
add the coeficients of like terms
y = x²+7x+12 is standard form of given equation.