We know that molarity is the number of moles of solute dissolved per litre of solution
[tex]Molarity=\frac{molesofsolute}{volume-of-solution}[/tex]
Moles = mass / molar mass
molar mass of NaCl = atomic mass of Na + atomic mass of Cl = 23+ 35.5 = 58.5
[tex]moles=\frac{225}{58.5}=3.85[/tex]
therefore
[tex]molarity=\frac{3.85}{0.25}=15.4M[/tex]
Thus molarity of given solution will be 15.4 M
