Answer:
option (3) and (4) are correct.
Step-by-step explanation:
We are given an inequality x + 3y ≥ -8
To check out of given ordered pair which satisfies the above inequality ,
Consider each point and we put them in the given inequality if they satisfy it they are solution to the given equation.
1) (-5, -1)
Substitute x = -5 and y = -1 in x + 3y ≥ -8 We get,
x + 3y ≥ -8 ⇒ (-5)+ 3(-1) ≥ -8 ⇒ (-5) - 3 ≥ -8 ⇒ -9 ≥ -8 (not true) as -8 ≥ -9
2) (0, -3)
Substitute x = 0 and y = -3 in x + 3y ≥ -8 We get,
x + 3y ≥ -8 ⇒ (0)+ 3(-3) ≥ -8 ⇒ - 9 ≥ -8 (not true) as -8 ≥ -9
3) (-1, -2)
Substitute x = -1 and y = -2 in x + 3y ≥ -8 We get,
x + 3y ≥ -8 ⇒ (-1)+ 3(-2) ≥ -8 ⇒ (-1) - 6 ≥ -8 ⇒ -7 ≥ -8 (true).
4) (-6, 0)
Substitute x = -6 and y = 0 in x + 3y ≥ -8 We get,
x + 3y ≥ -8 ⇒ (-6)+ 3(0) ≥ -8 ⇒ (-6) ≥ -8 (true)
5) (-16, 2)
Substitute x = -16 and y = 2 in x + 3y ≥ -8 We get,
x + 3y ≥ -8 ⇒ (-16)+ 3(2) ≥ -8 ⇒ (-16) +6 ≥ -8 ⇒ -10 ≥ -8 (not true) as -8 ≥ -10
Hence, only (-1, -2) and (-6, 0) is correct.
Thus, option (3) and (4) are correct.
