Rakeem458
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Three consecutive even numbers have a sum between 84 and 96.
a. Write an inequality to find the three numbers. Let n represent the smallest even number.
b. Solve the inequality.


a. 84 ≤ n + (n + 2) + (n + 4) ≤ 96
b. 78 ≤ n ≤ 90


a. 84 < n + (n + 2) + (n + 4) < 96
b. 26 < n < 30


a. 84 < n + (n + 1) + (n + 2) < 96
b. 27 < n < 31


a. n + (n + 2) + (n + 4) < –84 or n + (n + 2) + (n + 4) > 96
b. n < –30 or n > 31

Respuesta :

wegnerkolmp2741o

Answer:

a. 84 < n + (n + 2) + (n + 4) < 96

b. 26 < n < 30


Step-by-step explanation:

Let n = 1st number

n+2   2nd  even number

n+4 = 3rd even number

The sum of these 3 numbers is

n+n+2+n+4

It must be between 84 and 96  (it does not include this 84 and 96)

84< n+n+2+n+4 < 96


Now we need to solve this

Combine like terms

84 < 3n +6< 96

Subtract 6 from all sides

84 -6 < 3n+6-6 < 96 -6

78 < 3n < 90

Divide all sides by 3

78/3 < 3n/3 < 90/3

26 < n< 30


ihafizarslan

Answer:

Step-by-step explanation:

Combine like terms

84 < 3n +6< 96

Subtract 6 from all sides

84 -6 < 3n+6-6 < 96 -6

78 < 3n < 90

Divide all sides by 3

78/3 < 3n/3 < 90/3

26 < n< 30

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