Answer:
The inductance of the coil is 20 mH
Explanation:
The coil is represented by inductance and resistance connected in series. The impedance of such a circuit is as follows:
[tex]Z^2=R^2+X_L^2[/tex]
We can use this relationship to determine the inductance:
[tex]X_L=2\pi fL=\sqrt{Z^2-R^2}\implies L=\frac{\sqrt{Z^2-R^2}}{2\pi f}\\L=\frac{\sqrt{200^2-60^2}\Omega}{2\pi 1500 \frac{1}{s}}=0.020\Omega\cdot s=20 mH[/tex]
