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The probability of drawing two red balls from a jar at random without replacement is 3/10. The probabilty of drawing a red ball first is 9/16.

What is the probability of drawing a second Redball, given that the first ball drawn was red?

A. 69/80

B. 8/15

C. 21/80

D. 27/160

Respuesta :

robert7248

Answer:

B. [tex]p = \frac{8}{15}[/tex]

Step-by-step explanation:

The probability of selecting a red and then a red without replacement is as follows:

[tex]\frac{9x}{16} * \frac{9x}{16} -1[/tex]

This equals the given probability of [tex]\frac{3}{10}[/tex]

More simply, we have the equaiton:

[tex]\frac{9}{16} * P = \frac{3}{10}[/tex]

So, [tex]p = \frac{8}{15}[/tex]

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