A dog chases a cat in a circular path around the base of a tree. the velocity of the dog is 5.4 m/s. if the centripetal acceleration of the dog is 48.6 m/s2, what is the radius of the path? 0.11 meters 0.60 meters 9.0 meters 17 meters

Respuesta :

Its 0.6 pal, had the same question earlier and that's what i found. Hope it helps ;)

Answer:

The correct answer is option B, [tex]0.6 m\\[/tex]

Explanation:

Centripetal acceleration [tex]= \frac{v^2}{r}\\[/tex]

where "v" is the velocity of dog on the circular path

"r" is the radius of the circular path

Substituting the given values in above equation we get -

[tex]a = \frac{v^2}{r} \\48.6 \frac{m}{s^2} = \frac{ (5.4 \frac{m}{s})^2 }{r}\\r = 0.6 m\\[/tex]