Respuesta :
After balancing the chemical equation, what are the coefficients for these compounds?
H2S
⇒ 3
HNO3
⇒ 2
Works for EDG
Answer:
Coefficient of [tex]H_2S[/tex] = 3
Coefficient of [tex]HNO_3[/tex] = 2
Coefficient of [tex]NO[/tex] = 2
Coefficient of [tex]H_2O[/tex] = 4
Coefficient of [tex]S[/tex] = 3
Explanation:
Overall reaction
[tex]H_2S + HNO_3\rightarrow S + NO + H_2O[/tex]
Reduction half-reaction:
[tex]N^{+5} + 3e^-\rightarrow N^{+2}[/tex]...(1)
Oxidation half-reaction:
[tex] S^[-2}\rightarrow S + 2e^-[/tex]...(2)
2×(1) + 3×(2)
[tex]2N^{+5} + 6e^-+3S^[-2}\rightarrow 2N^{+2}+3S + 6e^-[/tex]
[tex]2N^{+5} +3S^[-2}\rightarrow 2N^{+2}+3S[/tex]
[tex]3H_2S + 2HNO_3\rightarrow 3S + 2NO + 4H_2O[/tex]
Coefficient of [tex]H_2S[/tex] = 3
Coefficient of [tex]HNO_3[/tex] = 2
Coefficient of [tex]NO[/tex] = 2
Coefficient of [tex]H_2O[/tex] = 4
Coefficient of [tex]S[/tex] = 3
