Answer: The average velocity of the atoms 847.33 m/s.
Explanation:
Moles of the neon = 1.00
Temperature of the gas : 288 K
Mass of the gas = 0.01000
R = 8.31 J/mol K
[tex]\frac{1}{2}mv^2=\frac{3}{2}\times nRT[/tex]
[tex]\frac{1}{2}0.01000 kg\times v^2=\frac{3}{2}\times 1.00\times 8.31 J/mol.K\times 288 K[/tex]
[tex]v^2=\frac{2\times 3\times 1.00\times 8.31 J/mol.K\times 288 K}{1\times 2\times 0.01000 kg}=717,948[/tex]
[tex]v=847.33 m/s[/tex]
The average velocity of the atoms 847.33 m/s.
