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Which of the following equations has the correct products and is balanced correctly for a reaction between Na3PO4 and KOH?

A)
Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction

B)
Na3PO4 + KOH → Na3OH + KPO4, because K increases in charge from 1+ to 3+ when it is replaced

C)
Na3PO4 + KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction

D)
Na3PO4 + KOH → Na3OH + K3PO4, because K increases in charge from 1+ to 3+ when it is replaced

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Dejanras

The answer is: A) Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction.

This chemical reaction is double displacement reaction - cations (K⁺ and Na⁺) and anions (PO₄³⁻⁻ and OH⁻) of the two reactants switch places and form two new compounds.  

Na₃PO₄ is sodium phosphate.  

KOH is potassium hydroxide.  

NaOH is sodium hydroxide.  

K₃PO₄ is potassium phosphate.  

According to the mass conservation law, there are same number of atoms on both side of balanced chemical reaction.

Answer:

A - Na3PO4 + 3KOH → 3NaOH + K3PO4, because K retains the same charge throughout the reaction

Explanation:

Did the test and got it right

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