Respuesta :
Answer:
Option D is correct that she took 3 pounds of jellybeans and 2 pounds of chocolate drops
Step-by-step explanation:
Given :
Terri wants jelly beans and chocolate drops.
Jelly beans sell for $0.90 per pound
Chocolate drops sell for $0.70 per pound.
Terri’s bag weighs 5 pounds
It costs $4.10.
To Find : How much she bought jellybeans and chocolate drops?
Solution :
Let she took x pounds of jellybeans.
Let she took y pounds of chocolate drops.
Since we are given that her bag weighs 5 pounds .
⇒[tex]x+y=5[/tex] ---(A)
Now cost of 1 pound of jelly beans = $0.90
So, Cost of x pounds of jellybeans. = $0.90 x
Now cost of 1 pound of chocolate drops. =$0.70
So, Cost of y pounds of chocolate drops. = $0.70 y
Since we are given that total cost of her bag of 5 pounds is $4.10
⇒[tex]0.90 x+0.70 y= 4.10[/tex] ---(B)
Solving A and B by using substitution method
Substitute value of x from (A) in (B)
⇒[tex]0.90 (5-y)+0.70 y= 4.10[/tex]
⇒[tex]4.5-0.90 y+0.70 y= 4.10[/tex]
⇒[tex]4.5-0.20 y= 4.10[/tex]
⇒[tex]4.5-4.10= 0.20 y[/tex]
⇒[tex]0.4= 0.20 y[/tex]
⇒[tex]\frac{0.4}{0.20} =y[/tex]
⇒[tex]2 =y[/tex]
Thus, she took y = 2 pounds of chocolate drops.
Now to calculate x substitute this value of y in (A)
⇒[tex]x+2=5[/tex]
⇒[tex]x=5-2[/tex]
⇒[tex]x=3[/tex]
Thus, she took x = 3 pounds of jellybeans
Hence , Option D is correct that she took 3 pounds of jellybeans and 2 pounds of chocolate drops
