Answer : The volume of the gas is, 8.24018 L
Solution : Given,
Moles of gas = 2 moles
Pressure of gas = 1 atm
Temperature of gas = 50 K
Molar volume correction factor, b = 0.01709 L/mole
Gas constant, R = 0.08206 L atm/mole K
Formula used for real gas :
[tex](P+\frac{an^2}{V^2})(V-nb)=nRT[/tex]
where,
P = pressure of gas
V = volume of gas
T = temperature of gas
R= gas constant
n = number of moles of gas
b = molar volume correction factor
a = pressure correction factor
The value of 'a' is zero
Now put all the given values in this formula, we get the volume of gas.
[tex](P)(V-nb)=nRT[/tex]
[tex]V=\frac{nRT}{P}+nb[/tex]
[tex]V=\frac{2\times 0.08206Latm/moleK\times 50K}{1atm}+(2\times 0.01709L/mole)=8.24018L[/tex]
Therefore, the volume of the gas is, 8.24018 L
