The teacher asked 4 students to measure 4 different objects. The table shown represents their measurements. Which student had the largest percent error?

The teacher asked 4 students to measure 4 different objects The table shown represents their measurements Which student had the largest percent error class=

Respuesta :

the correct answer is student four because it was off the most  

Answer:

Student #4


Step-by-step explanation:

The formula for percentage error is given below. We will use this formula for all the four students and figure out whose error is the most.

Percentage Error =  [tex]|\frac{MeasuredValue-ActualValue}{ActualValue}|*100[/tex]


  • For student 1:

% Error =  [tex]|\frac{49-50}{50}|*100\\=|-0.02|*100\\=(0.02)(100)\\=2[/tex]

  • For student 2:

% Error =  [tex]|\frac{25.5-25}{25}|*100\\=|0.02|*100\\=(0.02)(100)\\=2[/tex]

  • For student 3:

% Error =  [tex]|\frac{7.5-8}{8}|*100\\=|-0.0625|*100\\=(0.0625)(100)\\=6.25[/tex]

  • For student 4:

% Error =  [tex]|\frac{2.1-1.6}{1.6}|*100\\=|0.3125|*100\\=(0.3125)(100)\\=31.25[/tex]


Clearly, 31.25% error of student #4 is the highest.