Answer:
the minimum is (1,-9)
Step-by-step explanation:
y = 5x^2 - 10x - 4
since the parabola opens upward 5>0, this will have a minimum
it will occur along the axis of symmetry h=-b/2a
y =ax^2 +bx+c
h = -(-10)/2*5
h = 10/10 =1
the minimum occurs at x =1
the y value for the minimum is calculated by substituting x =1 back into the equation
y = 5 * 1^2 - 10*1 -4
y = 5*1^2 -10 -4
y = 5-10-4
y = -9
the minimum is (1,-9)
