Answer:
The width is [tex]\frac{17}{3}[/tex]
Step-by-step explanation:
First, we need to find the value of x.
To do this we need to multiply the two equations of the line because (length x width = area)
(2x + 5) (3x - 1)
Multiply out:
6x² -2x + 15x - 5
Simplified:
6x² +13x - 5
Factorise into two brackets:
(2x+5)(3x-1) = 0
x = [tex]\frac{-5}{2}[/tex] or x = [tex]\frac{1}{3}[/tex]
X has to be one third because it cannot be -2.5 because you cannot have a negative measurement.
Because the equation of the width is 2x + 5 simply plug the value of x into this:
[tex]2(\frac{1}{3}) + 5[/tex]
= [tex]\frac{17}{3}[/tex]
