Respuesta :

Answer:

Solution: Three consecutive ood integers are: x, x+2, x+4. Since their sum is 141 we write the equation: x+x+2+x+4=141, 3x+6=141, 3x=135, x=45. The first ood number is 45, the second 45+2=47 and the third 47+2=49.



The integers will be "70" and "71".

Let,

The two consecutive numbers be:

  • x
  • (x+1)

According to the question,

→ [tex]x+(x+1) = 141[/tex]

By solving the expression, we get

→    [tex]x+x+1 =141[/tex]

→        [tex]2x+1=141[/tex]

By subtracting "1" from both sides, we get

→  [tex]2x+1-1=141-1[/tex]

→              [tex]2x=140[/tex]

→                [tex]x = \frac{140}{2}[/tex]

                 [tex]x = 70[/tex]

and,

→ [tex]x+1 = 70+1[/tex]

            [tex]= 71[/tex]

Thus the above answer is correct.

Learn more about consecutive integers, we get

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