Answer : The pressure of the gas is, 0.964 atm
Solution : Given,
Volume of gas = 9040 ml = 9.040 L (1 L = 1000 ml)
Moles of gas = 0.447 moles
Temperature of gas = [tex]-35.50^oC=237.5K[/tex] [tex](0^oC=273K)[/tex]
Using ideal gas equation,
[tex]PV=nRT[/tex]
where,
P = pressure of the gas
V = volume of the gas
T = temperature of the gas
n = number of moles of gas
R = gas constant = [tex]0.0821Latm/moleK[/tex]
Now put all the given values in this formula, we get the pressure of the gas.
[tex]P(9.040L)=(0.447moles)\times (0.0821Latm/moleK)\times (237.5K)[/tex]
By rearranging the terms, we get
[tex]P=0.964atm[/tex]
Therefore, the pressure of the gas is, 0.964 atm
